7x-4)^2-3(X+5)^2=4(X+)(X-1)-2

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Solution for 7x-4)^2-3(X+5)^2=4(X+)(X-1)-2 equation: 



7x-4)^2-3(x+5)^2=4(x+)(x-1)-2

We move all terms to the left:

7x-4)^2-3(x+5)^2-(4(x+)(x-1)-2)=0

We add all the numbers together, and all the variables

7x-4)^2-3(x+5)^2-(4(+x)(x-1)-2)=0

We add all the numbers together, and all the variables

7x-4)^2-3(x+5)^2-(4(+x)(x-1)=0

We multiply parentheses ..

5)^2-(4(+x^2-1x)+7x-4)^2-3(x=0

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